Răspuns:
xm=-b/2a ; ym=-Δ/4a ; xm=10/10/=-1 ; Δ=b²-4ac=100-4 x 5 x 16=100-320=-220 ; ym= 220/20=11 ;
Explicație pas cu pas:
[tex]f:\mathbb{R}\to \mathbb{R},\quad f(x) = 5x^2-10x+16\\ \\\\\left.\begin{aligned} f(x) &= 5x^2-10x+16 \\ &= 5x^2-10x+5+11 \\ &= 5(x^2-2x+1)+11 \\ &= \underset{\geq 0}{\underbrace{5(x-1)^2}}+11\end{aligned}\right|\,\Rightarrow \,f_{\text{min}} = 11[/tex]
