vă rog ajutatima cu un raspuns

Bună!
[tex]\frac{3}{10} +\frac{3x-2}{4 } =1\frac{3}{10} -\frac{2x-4}{5} <=>\\[/tex]
[tex]<=> \frac{3x-2}{4} +\frac{2x-4}{5}=\frac{13}{10}-\frac{3}{10} <=>[/tex]
[tex]<=> ^{5)} \frac{3x-2}{4} +^{4)} \frac{2x-4}{5} =1 /*20 <=>\\[/tex]
[tex]<=> 15x-10+8x-16=20 <=>[/tex]
[tex]<=> 23x=20+26 => 23x=46 => x=2[/tex]
→[tex]1\frac{3}{10} =\frac{1*10+3}{10} =\frac{13}{10}[/tex]
3/10+(3x-2)/4=1 3/10-(2x-4)/5
3/10+(3x-2)/4=13/10-(2x-4)/5
6/20+5(3x-2)/20=26/20-4(2x-4)/20
6+5(3x-2)=26-4(2x-4)
6+15x-10=26-8x+16
15x-4= -8x+42
15x+8x=42+4
23x=46
x=46:23
x=2