Răspuns:
Explicație:
272 g H2S
M=2+32=34--------> 34g/moli
-se afla nr. de moli din 272g H2S
n= 272g : 34 g/moli=8 moli H2S
1mol H2S----------6,023.10²³molecule
8moli----------------------x
x= 8 . 6,023.10²³= 48,184.10²³ molecule H2S
10,2 kg NH3
10,2 kg= 10200 g NH3
M= 14 + 3=17-------> 17g/moli
n= 10200g : 17 g/moli=600 moli NH3
1mol NH3------------6,023.10²³ molecule
600moli-------------------y
y= 600 . 6,023.10²³= 36,138 .10²³ molecule NH3
