Aceste exercițiu, va rog!!

[tex] {2}^{2002} + ( {2}^{2} ) ^{1001} = {2}^{n} [/tex]
[tex] {2}^{2002} + 2 ^{2002} = {2}^{n} [/tex]
[tex]2 \times {2}^{2002} = {2}^{n} [/tex]
[tex]2 {}^{2003} = 2 {}^{n} [/tex]
=>n=2003