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1+2+3+4+..1+3+5+7+...+122


Răspuns :

1+2+3+4+5+...+122=

=(122×123)÷2

=7.503

1+3+5+7+...+121=

=(1+2+3+...+122)-(2+4+6..+122)

=7.503-[2×(1+2+3+...+61)]

=7.503-3.782

=3.721

7.503+3.721=11.224

rezultatul final --> 11.224